9x^2+6x-33=2

Solution for 9x^2+6x-33=2 equation:

9x^2+6x-33=2

We move all terms to the left:

9x^2+6x-33-(2)=0

We add all the numbers together, and all the variables

9x^2+6x-35=0

a = 9; b = 6; c = -35;
Δ = b2-4ac
Δ = 62-4·9·(-35)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-36}{2*9}=\frac{-42}{18}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+36}{2*9}=\frac{30}{18}
=1+2/3
$